我正在使用 Spring Boot 创建一个 Web 服务。我正在尝试将 HATEOAS 引入端点。这是模型(DTO):public class MovieResponse { private Long id; private String name; private Date releaseDate; private Time runtime; private Float rating; private String storyline; private String poster; private String rated; private Date createdAt; private List<GenreResponse> genres = new ArrayList<>(); private List<MovieMediaResponse> videos = new ArrayList<>(); private List<MovieMediaResponse> photos = new ArrayList<>(); private List<MovieReviewResponse> reviews = new ArrayList<>(); private List<MovieCelebrityResponse> cast = new ArrayList<>(); private List<MovieCelebrityResponse> writers = new ArrayList<>(); private List<MovieCelebrityResponse> directors = new ArrayList<>(); // Getters & Setters}我还有一个PagedResponse包含页面信息的:public class PagedResponse<T> { private List<T> content; private int page; private int size; private long totalElements; private int totalPages; private boolean last; public PagedResponse() {} public PagedResponse(List<T> content, int page, int size, long totalElements, int totalPages, boolean last) { this.content = content; this.page = page; this.size = size; this.totalElements = totalElements; this.totalPages = totalPages; this.last = last; } // Getters & Setters}我getAllMovies在服务中也有返回PagedResponse<MovieResponse>.得到以下错误:无法解析方法“toResource(com.movies.mmdb.util.PagedResponse, com.movies.mmdb.controller.MovieResourceAssembler)”在这一行: return ResponseEntity.ok(this.pagedAssembler.toResource(response, this.movieResourceAssembler));我认为在我传递变量时toResource接受. org.springframework.data.domain.Page;responsePagedResponse我该如何解决?
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阿晨1998
TA贡献2037条经验 获得超6个赞
如果toResource
方法接收 aPage<T>
作为第一个参数,那么为什么不使用该数据类型?如果你需要扩展 Page 那么你的类应该实现这样的接口来实现方法签名:
public class PagedResponse<T> implements Page<MovieResponse>
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