如何从 Python 中的文本文件计算中位数？

Question

我有这个文本文件：Category;currency;sellerRating;Duration;endDay;ClosePrice;OpenPrice;Competitive?Music/Movie/Game;US;3249;5;Mon;0,01;0,01;NoMusic/Movie/Game;US;3249;5;Mon;0,01;0,01;NoMusic/Movie/Game;US;3249;5;Mon;0,01;0,01;NoMusic/Movie/Game;US;3249;5;Mon;0,01;0,01;NoMusic/Movie/Game;US;3249;5;Mon;0,01;0,01;NoMusic/Movie/Game;US;3249;5;Mon;0,01;0,01;NoMusic/Movie/Game;US;3249;5;Mon;0,01;0,01;NoAutomotive;US;3115;7;Tue;0,01;0,01;NoAutomotive;US;3115;7;Tue;0,01;0,01;NoAutomotive;US;3115;7;Tue;0,01;0,01;Yes实际文件中没有空格，否则会显示错误。我想计算每个类别的中位数。因此，例如，我想从 SellerRating 计算中位数。到目前为止我有这个（因为我还需要计算平均值，但我设法做到了）：import csvimport localeimport statisticsfrom pprint import pprint, pformatimport localelocale.setlocale(locale.LC_ALL, 'Dutch_Netherlands.1252')avg_names = 'sellerRating', 'Duration', 'ClosePrice', 'OpenPrice'averages = {avg_name: 0 for avg_name in avg_names}num_values = 0 with open('bijlage.txt', newline='') as bestand:     csvreader = csv.DictReader(bestand, delimiter=';')     for row in csvreader:        num_values += 1        for avg_name in avg_names:             averages[avg_name] += locale.atof(row[avg_name])for avg_name, total in averages.items():averages[avg_name] = total / num_valuesprint('raw results:')pprint(averages)print() print('Averages:')for avg_name in avg_names:    rounded = locale.format_string('%.2f', round(averages[avg_name], 2),                               grouping=True)    print('  {:<13} {:>10}'.format(avg_name, rounded))我尝试这样做： import statistics print (statistics.median(averages) 但这不起作用。谁能帮助我，因为我不知道从哪里开始？提前非常感谢！