如何在列表中查找以用户要求的某个字母开头的单词

Question

所以我正在尝试制作一个添加、删除、搜索、保存和加载列表的程序除了在列表中搜索第一个字母之外，我已经设法使一切正常程序会询问用户想搜索哪个字母 然后在列表中搜索用户输入的第一个字母我设法做的是：mylist = ["hello","world","how","you","doing"]for word in mylist:  print (word[0])它确实打印出每个单词的第一个字母hwhyd>>> 但我想做什么mylist = ["hello","world","how","you","doing"]letter = input("input a letter you would like to search ").lower()用户输入的字母将在整个列表中搜索找到所有以该字母开头的单词后，我希望它打印出找到的单词数，然后打印出用户请求的字母中找到的单词

Answer 1

使用列表理解 startswith

[i for i in mylist if i.startswith(letter)]

它与您正在做的类似，但您没有检查如下条件

mylist = ["hello","world","how","you","doing"]

for word in mylist:

      if word[0]==letter:

            print(word)

对.lower()列表中存在的字符串进行安全使用

mylist = ["Hello","world","how","you","doing"]

letter = 'h'

[i for i in mylist if i.lower().startswith(letter)] #["Hello","how"]

Answer 2

mylist = ["hello","world","how","you","doing"]

letter = input("input a letter you would like to search ").lower()

    input a letter you would like to search 'h'

list_starting_with_letter = [i for i in mylist if i[0].lower()==letter.lower()]

list_starting_with_letter

    ['hello', 'how']

print('Number of such words: '+ str(len(list_starting_with_letter)))

    Number of such words: 2

Answer 3

for word in list:

    if input() in word:

        print(word)

在那条线上的东西。它从列表中获取单词，然后针对该单词测试用户输入。