如果条件，则增加列表索引

Question

在迭代列表中的所有元素时，我想在遇到特定元素时跳过后面的两个元素，例如：l1 = ["a", "b", "c", "d", "e", "f"]for index, element in enumerate(l1):    if element == "b":        index = index + 2    else:        print(index, element)0 a2 c3 d4 e5 f

Answer 1

更改索引不会起作用，因为它是由枚举迭代器创建的。您可以next()自己调用迭代器：

l1 = ["a", "b", "c", "d", "e", "f"]

iter  = enumerate(l1)

for index, element in iter:

    if element == "b":

        next(iter, None) # None avoids error if b is at the end

    else:

        print(index, element)

0 a

3 d

4 e

5 f

Answer 2

l1 = ["a", "b", "c", "d", "e", "f"]

index = 0

while index < len(l1):

    if l1[index] == "b":

        index += 2

    else:

        print(index, l1[index])

        index += 1

0 a

3 d

4 e

5 f

可以使用while循环。index += 1如果你想要 2 c