转换元组中列表的元素

Question

我有以下清单：list_c = ['42.2529, -73.7910', '42.079846, -76.499364', '42.361824, -73.597979', '42.035959, -73.580146']我想转换成这个：list_c2 =  [(42.2529, -73.7910),(42.079846, -76.499364),(42.361824, -73.597979),(42.035959, -73.580146)]我正在尝试的代码是：list_c2 = [(list_c[i]) for i in range(0, len(list_c))]print("list_c2 =", list_c)不幸的是，结果与 list_c

Answer 1

对不起，我最初误读了您的清单。要将其转换为浮点数对，您需要将split每个字符串放在其逗号上，然后将每个元素设为a float，然后将它们打包成一个元组：

list_c2 = [tuple(float(item) for item in s.split(',')) for s in list_c]

# [(42.2529, -73.791), (42.079846, -76.499364), (42.361824, -73.597979), (42.035959, -73.580146)]