使用 cron 运行 Go 方法

Question

我正在尝试编写一个程序，该程序将在特定时间间隔内连续调用一个方法。我正在使用 cron 库来尝试实现这一点，但是当我运行该程序时，它只会执行并完成而没有任何输出。下面是我正在尝试做的一个基本示例。非常感谢您的帮助！package mainimport (    "fmt"    "github.com/robfig/cron")func main() {    c := cron.New()    c.AddFunc("1 * * * * *", RunEverySecond)    c.Start()}func RunEverySecond() {    fmt.Println("----")}

Answer 1

为此使用外部包是矫枉过正的，该time包具有您需要的一切：

package main

import (

    "fmt"

    "time"

)

func main() {

    go func() {

        c := time.Tick(1 * time.Second)

        for range c {

            // Note this purposfully runs the function

            // in the same goroutine so we make sure there is

            // only ever one. If it might take a long time and

            // it's safe to have several running just add "go" here.

            RunEverySecond()

        }

    }()

    // Other processing or the rest of your program here.

    time.Sleep(5 * time.Second)

    // Or to block forever:

    //select {}

    // However, if doing that you could just stick the above for loop

    // right here without dropping it into a goroutine.

}

func RunEverySecond() {

    fmt.Println("----")

}