如何获得结果 (JSON PHP)

Question

我有个问题。我怎样才能得到结果？这是我的代码：<?php $api_e = file_get_contents('https://omnihost.tech/dashboard/hosts/'.$slug.'/api_ftp');$api = json_decode($api_e); ?><?php foreach($api as $file){ ?>    <tr>        <td>#</td>        <td><?= $file; ?></td>        <td>--</td>    </tr><?php } ?>我的 JSON 是：{"data": [".","..",".editorconfig",".gitignore",".htaccess",".well-known","README.md","application","assets","cgi-bin","composer.json","contributing.md","index.php","license.txt","readme.rst","system"]}错误：http : //prntscr.com/o98xau

Answer 1

您需要指定您需要打印的列，您可以尝试在下面打印文件名

<td><?= $file['12']; ?></td>

否则，您将循环打印数组中的所有数据，使用 2 个循环

<?php foreach($api as $file) { ?>

<?php foreach($file as $i => $item) { ?>

<tr>

<td><?= $i; ?></td>

<td><?= $item; ?></td>

<td>--</td>

</tr>

<?php } ?>

<?php } ?>