我正在使用 php 和 bootstrap 构建一个联系表单,我想在发生错误时显示 bootstrap 警报。所以我现在的问题是我已经让代码工作并且它检查错误但是在错误发生之前显示错误警报对话框我试图将错误对话框移到 HTML 下方,但我仍然遇到相同的错误$email = $name = $subject = $message = '';$errors = ['email' => '', 'name' => '', 'subject' => '', 'message' => ''];if (isset($_POST['submit'])) { // check email if (empty($_POST['email'])) { $errors['email'] = "An email is required !"; } else { $email = $_POST['email']; if (!filter_var($email, FILTER_VALIDATE_EMAIL)) { $errors['email'] = "Enter a validemail address !"; } } <div class="form-group"> <label for="email" class="bmd-label-floating">Email address</label> <input type="email" class="form-control" name="email" value="<?php htmlspecialchars($email)?>"> <div class="mt-2 alert alert-warning alert-dismissible fade show" role="alert"> <?php echo $errors['email'] ?> </div></div>预期的行为应该是在错误发生时在错误对话框中显示错误,而不是在错误发生之前出现错误对话框
2 回答
慕桂英3389331
TA贡献2036条经验 获得超8个赞
您想用 an 包装模态if以检查是否确实存在错误。
<?php if($errors['email']): ?>
<div class="mt-2 alert alert-warning alert-dismissible fade show" role="alert">
<?php echo $errors['email'] ?>
</div>
<?php endif; ?>
守着星空守着你
TA贡献1799条经验 获得超8个赞
在显示错误之前添加检查。喜欢下面
<?php
if(isset($errors['email']) && $errors['email']!=''){
?>
<div class="mt-2 alert alert-warning alert-dismissible fade show" role="alert">
<?php echo $errors['email']; ?>
</div>
<?php } ?>
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