找不到参数的方法 implementation()

Question

我已经为此抗争了一段时间，并尝试使用实现和编译，并遵循了无数 stackover 流和其他论坛帖子中的建议：根级 build.gradle：buildscript {    repositories {        google()        jcenter()        maven {            url "https://maven.google.com"        }    }    dependencies {        classpath 'com.android.tools.build:gradle:3.1.3'        classpath 'com.google.gms:google-services:4.0.2'    }}    allprojects {    repositories {        google()        jcenter()        maven {            url "https://maven.google.com"        }}..........    //This replaces project.properties w.r.t. build settingsproject.ext {  defaultBuildToolsVersion="25.0.2" //String  defaultMinSdkVersion=19 //Integer - Minimum requirement is Android 4.4  defaultTargetSdkVersion=28 //Integer - We ALWAYS target the latest by default  defaultCompileSdkVersion=28 //Integer - We ALWAYS compile with the latest by default}App build.gradle（我已编辑为包含整个应用程序 gradle 文件，而不是我认为只是包含此错误的部分。gradle-wrapper.properties:distributionBase=GRADLE_USER_HOMEdistributionPath=wrapper/distszipStoreBase=GRADLE_USER_HOMEzipStorePath=wrapper/distsdistributionUrl=https\://services.gradle.org/distributions/gradle-4.4-all.zip我正在执行 ./gradlew build

Answer 1

您应该从 buildscript 依赖项中取出 firebase-core 依赖项并将其放入您的应用程序级依赖项中：

dependencies {

    implementation fileTree(dir: 'libs', include: '*.jar')

    // SUB-PROJECT DEPENDENCIES START

    implementation(project(path: ":CordovaLib"))

    // SUB-PROJECT DEPENDENCIES END

    // put Firebase dependencies here to compile them into your app

    implementation 'com.google.firebase:firebase-core:16.0.1'

}