如何在python中删除相同的字符串

Question

我使用 python3.6 我想删除相同的字符串，这是我的代码。r = [['I1', 'I2'], ['I1', 'I3'], ['I1', 'I5'], ['I2', 'I3'], ['I2','I4'], ['I2', 'I5']]for v in range(len(r)):    for k in range(v+1,len(r)):        union = list(set(r[v]) | set(r[k]))        print(sorted(union))结果是：['I1', 'I2', 'I3']['I1', 'I2', 'I5']['I1', 'I2', 'I3']['I1', 'I2', 'I4']['I1', 'I2', 'I5']['I1', 'I3', 'I5']['I1', 'I2', 'I3']['I1', 'I2', 'I3', 'I4']['I1', 'I2', 'I3', 'I5']['I1', 'I2', 'I3', 'I5']['I1', 'I2', 'I4', 'I5']['I1', 'I2', 'I5']['I2', 'I3', 'I4']['I2', 'I3', 'I5']['I2', 'I4', 'I5']如何删除相同的字符串？

Answer 1

我创建Union_list以跟踪已打印的内容：

Union_list = [] 

r = [['I1', 'I2'], ['I1', 'I3'], ['I1', 'I5'], ['I2', 'I3'], ['I2','I4'], ['I2', 'I5']]

for v in range(len(r)):

    for k in range(v+1,len(r)):

        union = sorted(list(set(r[v]) | set(r[k])))

        if union not in Union_list:

            Union_list.append(union)

            print(union)

输出：

['I1', 'I2', 'I3']

['I1', 'I2', 'I5']

['I1', 'I2', 'I4']

['I1', 'I3', 'I5']

['I1', 'I2', 'I3', 'I4']

['I1', 'I2', 'I3', 'I5']

['I1', 'I2', 'I4', 'I5']

['I2', 'I3', 'I4']

['I2', 'I3', 'I5']

['I2', 'I4', 'I5']