打印列表的前 n 个不同值

Question

我想从列表中打印前 10 个不同的元素：top=10test=[1,1,1,2,3,4,5,6,7,8,9,10,11,12,13]for i in range(0,top):    if test[i]==1:        top=top+1    else:        print(test[i])它正在打印：2,3,4,5,6,7,8我期待：2,3,4,5,6,7,8,9,10,11我缺少什么？

Answer 1

使用 numpy

import numpy as np

top=10

test=[1,1,1,2,3,4,5,6,7,8,9,10,11,12,13]

test=np.unique(np.array(test))

test[test!=1][:top]

输出

array([ 2,  3,  4,  5,  6,  7,  8,  9, 10, 11])

Answer 2

我的解决方案

test = [1,1,1,2,3,4,5,6,7,8,9,10,11,12,13]

uniqueList = [num for num in set(test)] #creates a list of unique characters [1,2,3,4,5,6,7,8,9,10,11,12,13]

for num in range(0,11):

    if uniqueList[num] != 1: #skips one, since you wanted to start with two

        print(uniqueList[num])