Python-以给定格式编写句子

Question

我有一个包含一句话的文件。我让用户选择“行”和“列”的数量。我想检查一下我可以在这种表格中写多少次而不拆分单词。现在我希望文本的形式是这样的：输入：行= 3列= 10个文件来自文件：猫有狗。输出：猫有***狗。猫**有狗。**该程序无法拆分单词，并且无法在无法放置星星的地方进行拆分。这是我所做的代码的一部分，但我觉得我没有朝着好的方向发展。我的问题： 1. 如何改进我的代码？2. 如何让它既能算字又能算字？3. 此任务的一般提示。我的代码：import syscolumns, rows, path = sys.argv[1:]columns=int(columns)rows=int(rows)file=open(path,"r")text=file.read()list=list(text.split())length=len(list)for i in range(length):    k=len(lista[i])    if k<=columns:        print(list[i], end=" ")    else:        print("*") 

Answer 1

这比我想象的要艰难。可能有一个更简单的解决方案，但你可以试试这个：

list_of_words = text.split()

current_character_count_for_row = 0

current_string_for_row = ""

current_row = 1

how_many_times_has_sentence_been_written = 0

is_space_available = True

# Keep going until told to stop.

while is_space_available:

    for word in list_of_words:

        # If a word is too long for a row, then return false.

        if len(word) > columns:

            is_space_available = False

            break

        # Check if we can add word to row.

        if len(word) + current_character_count_for_row < columns:

            # If at start of row, then just add word if short enough.

            if current_character_count_for_row == 0:

                current_string_for_row = current_string_for_row + word

                current_character_count_for_row += len(word)

            # otherwise, add word with a space before it.

            else:

                current_string_for_row = current_string_for_row +" " + word

                current_character_count_for_row += len(word) + 1

        # Word doesn't fit into row.

        else:

            # Fill rest of current row with *'s.

            current_string_for_row = current_string_for_row + "*"*(columns - current_character_count_for_row)

            # Print it.

            print(current_string_for_row)

            # Break if on final row.

            if current_row == rows:

                is_space_available = False

                break

            # Otherwise start a new row with the word

            current_row +=1

            current_character_count_for_row = len(word)

            current_string_for_row = word

    if current_row > rows:

        is_space_available = False

        break

    # Have got to end of words. Increment the count, unless we've gone over the row count.

    if is_space_available:

        how_many_times_has_sentence_been_written +=1

print(how_many_times_has_sentence_been_written)