查看“Fluent Python”书中解释 的“双向隧道”功能的以下示例代码yield from,我有以下问题。from collections import namedtupleResult = namedtuple('Result', 'count average')# the subgeneratordef averager(): # <1> total = 0.0 count = 0 average = None while True: term = yield # <2> if term is None: # <3> break total += term count += 1 average = total/count return Result(count, average) # <4># the delegating generatordef grouper(results, key): # <5> while True: # <6> results[key] = yield from averager() # <7># the client code, a.k.a. the callerdef main(data): # <8> results = {} for key, values in data.items(): group = grouper(results, key) # <9> next(group) # <10> for value in values: group.send(value) # <11> group.send(None) # important! <12> print("wrapped up grouper") print(results)data = { 'girls;kg': [40.9, 38.5, 44.3, 42.2, 45.2, 41.7, 44.5, 38.0, 40.6, 44.5], 'girls;m': [1.6, 1.51, 1.4, 1.3, 1.41, 1.39, 1.33, 1.46, 1.45, 1.43], 'boys;kg': [39.0, 40.8, 43.2, 40.8, 43.1, 38.6, 41.4, 40.6, 36.3], 'boys;m': [1.38, 1.5, 1.32, 1.25, 1.37, 1.48, 1.25, 1.49, 1.46],}StopIteration当我用下面的委托生成器替换上面的委托生成器时,为什么会出现异常?def grouper(results, key): results[key] = yield from averager()从我到目前为止所学到的,从理论上讲,删除while True应该没问题。group.send(None)将导致averager()协程break并返回Result(...),该 将被传递给委托生成器。然后委托生成器将通过将其分配Result(...)给results[key].但正在发生的事情如下。Traceback (mostrecent call last): File "coroaverager3.py", line 111, in <module> main(data) File "coroaverager3.py", line 83, in main group.send(None) # important! <12>StopIteration任何见解?
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