动态保存数据php

Question

我已将 ajax 数据与表单中的所有数据一起发布。用户可以为以前的雇主动态添加带有行的块。[empName]也许 10 或 20 ... 或 2 ...如何捕捉以前雇主的数量并将其保存到变量中？这是帖子数据：["step-3"]=> string(1065) "{"empYrXp":"min10yexp","empName-1":"TEST PAYPAL TEST","empStr-1":"TEST ORDER PAYPAL","empCity-1":"Pleven","empState-1":"CT","empContactPerson-1":"mbnmbnmbnm","empContactPersonPhone-1":"999-999-9999","empFromDate-1":"08-2013","empToDate-1":"06-2019","empPositionHeld-1":"bnmb","empReasonForLeaving-1":"nmbnmbnmbnm","empWereSubject-1":"No","empWasPrevJobDesignated-1":"No","empName-2":"TEST PAYPAL TEST","empStr-2":"TEST ORDER PAYPAL","empCity-2":"Pleven","empState-2":"CA","empContactPerson-2":"fghfhfhfgh","empContactPersonPhone-2":"999-999-9999","empFromDate-2":"02-2008","empToDate-2":"08-2013","empPositionHeld-2":"fghfgh","empReasonForLeaving-2":"fghfghfgh","empWereSubject-2":"No","empWasPrevJobDesignated-2":"No","empName-3":"TEST TEST","empStr-3":"TEST ORDER PAYPAL","empCity-3":"Pleven","empState-3":"CA","empContactPerson-3":"sdfsdfsdfsdf","empContactPersonPhone-3":"999-999-9999","empFromDate-3":"01-2006","empToDate-3":"01-2006","empPositionHeld-3":"sdfsdfs","empReasonForLeaving-3":"dfsdfsdfsdf","empWereSubject-3":"No","empWasPrevJobDesignated-3":"No"}" 我试着像这样计算以前的雇主$countAllEmp = ( count($jsonDecode3) - 1 ) / 12;

Answer 1

不知道您如何获得 json，但表单支持命名，[]从而在服务器端生成数组：

<input name="someName[]" />

<input name="someName[]" />

<input name="someName[]" />

尝试输出$_POST['someName']，它将是具有 3 个元素的 0 索引数组。

此外，您可以[]显式定义索引：

<input name="someName[11]" />

<input name="someName[12]" />

<input name="someName[13]" />

尝试输出$_POST['someName']，它将是具有 3 个键的数组 - 11, 12, 13。

所以，你必须重新命名字段来代替empName-，empStr-等等-使用[]的符号：empName[]，empStr[]等等。