1 回答
TA贡献1111条经验 获得超0个赞
我做到了!在自定义序列化程序的帮助下。
首先是根元素:
@JacksonXmlRootElement(localName = "Root")
class Root {
@JacksonXmlElementWrapper(useWrapping = false)
private List<Wrapper> keyValueList;
// getters, setters
}
Key和Value对的包装类:
@JsonSerialize(using = WrapperSerializer.class)
class Wrapper {
private String key;
private String value;
// getters, setters, all args constructors
}
和序列化器:
public class WrapperSerializer extends StdSerializer<Wrapper> {
public WrapperSerializer() {
this(Wrapper.class);
}
protected WrapperSerializer(Class<Wrapper> t) {
super(t);
}
@Override
public void serialize(Wrapper value, JsonGenerator gen, SerializerProvider provider) throws IOException {
gen.writeRaw(new StringBuilder()
.append("<Key>")
.append(value.getKey())
.append("</Key>")
.append("<Value>")
.append(value.getValue())
.append("</Value>")
.toString());
}
}
让我们测试一下:
Root ref = new Root();
ref.setKeyValueList(Arrays.asList(
new Wrapper("k1", "v1"),
new Wrapper("k2", "v2")));
XmlMapper xmlMapper = new XmlMapper();
String output = xmlMapper.writeValueAsString(ref);
System.out.println(output);
结果:
<Root><Key>k1</Key><Value>v1</Value><Key>k2</Key><Value>v2</Value></Root>
添加回答
举报