大家好,我有实体:孩子:@EDIT 感谢@MithatKonuk@Entity@Table(name="child")public class Child { @Id @GeneratedValue(strategy = GenerationType.IDENTITY) @Column(name="ID") private int id; @Column(name="FirstName") private String firstName; @Column(name="SecondName") private String secondName; @Column(name="PESEL") private String PESEL; @Column(name="Sex") private String sex; @JsonBackReference @ManyToOne(cascade = CascadeType.ALL) @JoinColumn(name="familyid",referencedColumnName = "id") private Family family;和家人:@EDIT 感谢@MithatKonuk@Entity@Table(name="family")public class Family { @Id @GeneratedValue(strategy = GenerationType.IDENTITY) @Column(name = "ID") private int id; @OneToOne(cascade = CascadeType.ALL) private Father father; @JsonManagedReference @OneToMany(mappedBy = "family",fetch=FetchType.EAGER,cascade = CascadeType.ALL) private List<Child> childList;我想获得属于家庭一部分的儿童名单。我尝试进行查询:@EDIT 感谢@MithatKonuk@Transactionalpublic List<Child> findAllChild(int id) { // TODO Auto-generated method stub HibernateUtil.initManager(); HibernateUtil.getEntityManager().clear(); Query query = HibernateUtil.getEntityManager().createQuery("SELECT child FROM Child child FETCH JOIN child.family u WHERE u.id = :userId "); query.setParameter("userId",id); List<Child> result = query.getResultList(); HibernateUtil.shutdown(); return result;}我需要你的帮助。@Edit 好的,所以我将此代码更新为完整实体。你还需要一些吗?很抱歉,这可能很容易,但我正在学习 hibernate,但我不知道这个 cos 出了什么问题。谢谢你的回答。
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