我正在编辑一个应该在值更改时更新数据库的代码,但是它不起作用,希望有人能帮我修复它。我正在使用 DISTINCT 获取数据并需要同时更新一些数据。它可以显示值,但不能保存在数据库中。例如,我将使用 DISTINCT 来获取一些具有相同日期的数据,并且我将使用该代码同时更改这些数据中的值。索引.php<script> window.onload = function() { $(".cal_amount").change(function() { var auto_array = {}; //Step 1- On change use The closest() method to get the all input elements value of selected element row. form_data = $(this).closest('tr').find('input, select'); //Step 2- On change Use map to store input elements value with name as key in the array. var myArray = $.map(form_data, function(element) { auto_array[element.name] = element.value; //return {name: element.name, value: element.value}; }); form_data = $(this).closest('tr').find('input,select').serialize(); $.ajax({ data: { action: 'update_price', form_data: form_data, }, url: 'updates_ok.php', type: 'post', beforeSend: function() { }, success: function(data) { if(data == 1){ alert('update sucessful')} } }); }); }; </script><script> window.onload = function() { $(".day_record").change(function() { var auto_array = {}; //Step 1- On change use The closest() method to get the all input elements value of selected element row. form_data = $(this).closest('tr').find('input, select'); //Step 2- On change Use map to store input elements value with name as key in the array. var myArray = $.map(form_data, function(element) { auto_array[element.name] = element.value; //return {name: element.name, value: element.value}; });
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