在 PHP 中使用 ENTER 在字段值之一中接收 JSON POST

Question

当“描述”字段具有“输入”（换行符）时，API 失败。用于检查用户发送的所有参数的图像下面的代码从发布的 JSON 中获取数据。     // get posted data     $jason_value = json_decode(file_get_contents("php://input"));     $crm_id = $jason_value->data->crmId;     $descriptions = $jason_value->data->descriptions;我想接受描述作为字符串一行。descriptions = "10+ windows 现代风格 7057655959"。我无权访问用户输入描述的程序，我可以在其中添加验证并将其转换为 \n。转换后低于字符串{ "jwt": "eyJ0", "data": { "crmId": "15876047", "geoconceptAppointmentId": "15876","geoconceptCustomerId": "15876047","status": "Rejected","appointmentDateTime": "","firstName": "Nick Test","lastName": "PA","address": "9112 RUE Tom","city": "MONTREAL","state": "QC","zip": "H2N1T1","country": "CAN","phoneNumber1": "5148332222","phoneNumber2": "5148332222","email": "[e-mail]","dateEntry": "2019-06-20 12:02","dateModify": "2019-06-20 12:02","preferredWayToContact": "","textMsgFlag": "Y","hearAboutUs": "Referral","perferredTime": "Anytime","descriptions": "I have to call at 5" pm. ","worklog": "This is the comment ","rejectReason": "Area | Region","referredByDC": "09999","referredByStoreUsername": "store215","assignedUsername": "","createdByUsername": "np","modifiedByUsername": "np","btgMarket": "Montreal"}}

Answer 1

你是对的，在 PHP7+ 中，文字制表符或换行符会导致 json 解析失败。file_get_contents("php://input")返回一个字符串，所以我看不出为什么你不能在尝试解析它之前过滤它。但也许我错过了一些东西。

//Catch Unix OR DOS line endings, but not both

$filter = Array("\n","\n\r");

$replace = " ";

$cleanJSON = str_replace($filter, $replace, file_get_contents("php://input");

$data = json_decode($cleanJSON));

我想指出，在这一点之后，您的代码引用了一个不存在的变量： $jason_value

$crm_id = $jason_value->data->crmId;

$descriptions = $jason_value->data->descriptions;

要引用您刚刚创建的对象的属性，请直接转到$data：

$crm_id = $data->crmId;

$descriptions = $data->descriptions;

我希望您想用空格替换换行符，但如果您实际遇到的内容在换行符之前有一个空格，则您可能只想要一个空字符串，但无法从我们拥有的内容中看出这一点。