最喜欢的食物 Java 程序出错了

Question

下面是我的Java程序。现在，程序正确运行的唯一方法是让最后一列最长。如果数组中的最后一列不是最长的，则输出不正确。例如，如果food数组在第二列中的元素比第三列中的元素多，如下所示：String[][] food = {        {"Bannana", "Apple", "Pear", "Orange"}, // fruits        {"GreenBean", "Iceburg", "Spenach", "peas", "carrots", "potatoes", "beans"}, // vegetables         {"Steak",   "Baccon", "Beef", "TurkeyB", "TurkeyBacon", "Chicken"} // meats };然后，例如，如果chicken输入作为输入，则输出是这样的：Yo have no favorite foodYour favorite food is Chicken而且，例如，如果输入是biscuit，那么输出是这样的：Yo have no favorite foodYo have no favorite food那么，有没有办法只打印"Yo have no favorite food"一次或正确打印出最喜欢的食物，而最后一列不必最长？这是代码：package com.begg;import java.util.*;public class List {    static Scanner sc = new Scanner(System.in);    public static void main(String[] args) {        String[][] food = {                {"Bannana", "Apple", "Pear", "Orange"}, // fruits                {"GreenBean", "Iceburg", "Spenach", "peas"}, // vegetables                 {"Steak",   "Baccon", "Beef", "TurkeyB", "TurkeyBacon", "Chicken"} // meats         };        for(int row = 0; row < food.length; row++) {            for (int col = 0; col < food[row].length; col ++) {                System.out.print(food[row][col] + ", ");            }            System.out.println();        }        System.out.println("Enter your favorite out of the options above:");        String k = sc.next();        loop2:        for(int row2 = 0; row2<food.length; row2++) {            for (int col2 = 0; col2< food[row2].length; col2++) {                if (k.equalsIgnoreCase(food[row2][col2])) {                    System.out.println("Your favorite food is " + food[row2][col2]);                    break loop2;                }                else if (!(k.equalsIgnoreCase(food[row2][col2])) & col2== 5 ) {                    System.out.println("Yo have no favorite food");                }            }        }    }}

Answer 1

改变这部分：

else if (!(k.equalsIgnoreCase(food[row2][col2])) & col2== 5 ) {

    System.out.println("Yo have no favorite food");

}

对此：

else if (!(k.equalsIgnoreCase(food[row2][col2])) && row2 == food.length-1 && col2 == food[row2].length-1) {

    System.out.println("Yo have no favorite food");

}

应该做我认为你正在寻找的。编辑else if检查是否已检查数组的所有值（与哪一列更长无关），如果没有与输入匹配，则它将执行System.out.println("Yo have no favorite food");一次。