绘图，半极坐标图，将角轴设置为 -90° 到 90°

Question

我正在尝试用 python 绘制一个极坐标图，并以 plotly 显示二维图像中纤维的方向（请参阅下面的代码）。如果您能向我展示如何更改角轴（当前范围从 0° 到 360°）以匹配我的数据范围从 -90° 到 90°，那就太好了。下面是半极坐标图的示例图像、我的数据格式和我的代码。import plotly.graph_objs as gofrom plotly import plotlyimport plotly.offline as offlineimport numpy as np# datax= np.genfromtxt(see data image) y= np.genfromtxt(see data image)trace = [    go.Scatterpolar(        r = [y], #radial coordinates        theta = [x], #angular coordinates        mode = 'markers',        marker = dict(            color = 'peru'        )    )]layout = go.Layout(    showlegend = True,    polar = dict(        domain = dict( # set chart size and position         x = [0, 0.8],        y = [0.3, 0.8]),        sector = [0, 180],   # set chart shape (half or full)        angularaxis = dict(            thetaunit = "degrees",            dtick = 10),        radialaxis = dict(            range = [1, 8000])      ))fig = go.Figure(data=trace, layout=layout)offline.plot(fig)xy数据纤维取向的半极坐标图

Answer 1

如果有人知道如何旋转它（逆时针旋转 90°）并镜像它（-90 左，0 上，90 右），请告诉我。我试图rotation=和direction=命令，但与它们没有工作，碰撞sector=命令为角轴设置范围从-90到90。

干杯，罗恩

import plotly.graph_objs as go

from plotly import plotly

import plotly.offline as offline

import numpy as np

import plotly

# data

x= np.genfromtxt("data.csv", delimiter=",", usecols=(0), skip_header=1, encoding = 'unicode_escape')

y= np.genfromtxt("data.csv", delimiter=",", usecols=(1), skip_header=1, encoding = 'unicode_escape')

trace = [

    go.Scatterpolar(

        r = [float(a) for a in y], #radial coordinates

        theta = [float(b) for b in x], #angular coordinates

        mode = 'lines',

        marker = dict(

            color = 'peru'

        )

    )

]

layout = go.Layout(

    showlegend = True,

    legend=dict(

        x=1),

    polar = dict(

        domain = dict( # set chart size and position 

        x = [0, 1],

        y = [0, 1]),

        sector = [-90,90],   # set chart shape (half or full)

        angularaxis = dict(

            thetaunit = "degrees",

            dtick = 10,

            #rotation = -90, #does not work

            #direction = "clockwise" # does not work

            ),

        radialaxis = dict(

            range = [1, 6500])

))

fig = go.Figure(data=trace, layout=layout)

offline.plot(fig)

Answer 2

好的，所以我只通过进行以下更改来获得输出：

• 更改go.Layout sector=[0, 180]为sector=[-90, 90]

• 更改go.Scatterplot r=[y]为r=[float(a) for a in y]

• 更改go.Scatterplot theta=[x]为theta=[float(b) for b in x]

第一个更改创建了您需要的范围（-90 到 90）

第二次和第三次更改将结果从np.genfromtext()字符串转换为数字（尽管如果您的数据在x和 中已经是数字，则可能不需要这些更改y）。

我的代码现在看起来像这样：

import plotly.graph_objs as go

import plotly.offline as offline

import numpy as np

# data

x = np.genfromtxt([str(i) for i in range(-90, 91)])

y = np.genfromtxt([str(i * 25 + np.random.randint(1000, 2500)) for i in range(0, 181)])

trace = [

    go.Scatterpolar(

        r=[float(a) for a in y],  # radial coordinates

        theta=[float(b) for b in x],  # angular coordinates

        thetaunit="degrees",

        mode='markers',

        marker=dict(

            color='peru'

        )

    )

]

layout = go.Layout(

    showlegend=True,

    polar=dict(

        domain=dict(  # set chart size and position

            x=[0, 0.8],

            y=[0.3, 0.8]),

        sector=[0, 1800],  # set chart shape (half or full)

        angularaxis=dict(

            thetaunit="degrees",

            dtick=10,

            rotation=90,

            direction='clockwise'),

        radialaxis=dict(

            range=[1, 8000])

    )

)

fig = go.Figure(data=trace, layout=layout)

offline.plot(fig)

这些变化足以产生以下结果：