Go：排序数组，如果在“Less(i, j int)”中发现错误，则删除元素

Question

鉴于以下 structtype Point struct {    datetimeRecorded time.Time}// Returns true if the point was recorded before the comparison point.// If datetime is not available return false and an errorfunc (p1 Point) RecordedBefore(p2 Point) (isBefore bool, err error) {    if (p1.datetimeRecorded.IsZero()) || (p2.datetimeRecorded.IsZero()) {        err = ErrNoDatetime    } else {        isBefore = p1.datetimeRecorded.Before(p2.datetimeRecorded)    }    return}我想[]Point按datetimeRecorded属性对 a 进行排序。我有以下（有效）：type ByDatetimeRecorded []Pointfunc (a ByDatetimeRecorded) Len() int {    return len(a)}func (a ByDatetimeRecorded) Swap(i, j int) {    a[i], a[j] = a[j], a[i]}func (a ByDatetimeRecorded) Less(i, j int) bool {    swap, _ := a[i].RecordedBefore(a[j])    return swap}但是，如果datetimeRecorded在任一比较中都未初始化该属性，error则将被捕获并且不会交换点（返回false）。是否可以捕获此错误并将其从数组中删除？类似的东西：func (a ByDatetimeRecorded) Less(i, j int) bool {    swap, err := a[i].RecordedBefore(a[j])    if err != nil {        // Remove element here    }    return swap}编辑 1我可能必须更具体地说明要删除的元素，因此这可能更有意义：func (a ByDatetimeRecorded) Less(i, j int) bool {    if a[i].datetimeRecorded.IsZero() {        // Drop a[i]    }    if a[j].datetimeRecorded.IsZero() {        // Drop a[j]    }    swap, _ := a[i].RecordedBefore(a[j])    return swap}

Answer 1

标准排序包不会从切片中删除元素。在排序之前过滤掉切片中的零值。

  i := 0

  for _, p := range points {

      if !p.datetimeRecorded.IsZero() {

         points[i] = p

         i++

      }

  }

  points = points[:i]

  sort.Sort(ByDatetimeRecorded(points))