1 回答
TA贡献1828条经验 获得超3个赞
以下是按名称获取字符串字段的方法:
package main
import (
"fmt"
"reflect"
)
func main() {
a := Order{A: "asdf", B: 123}
fmt.Println(a)
fmt.Println(GetStringValueByFieldName(a, "A"))
fmt.Println(GetStringValueByFieldName(&a, "A"))
fmt.Println(GetStringValueByFieldName(a, "B"))
fmt.Println(GetStringValueByFieldName(0, "B"))
fmt.Println(GetStringValueByFieldName(a, "C"))
}
type Order struct {
A string
B int64
}
func GetStringValueByFieldName(n interface{}, field_name string) (string, bool) {
s := reflect.ValueOf(n)
if s.Kind() == reflect.Ptr {
s = s.Elem()
}
if s.Kind() != reflect.Struct {
return "", false
}
f := s.FieldByName(field_name)
if !f.IsValid() {
return "", false
}
switch f.Kind() {
case reflect.String:
return f.Interface().(string), true
case reflect.Int:
return strconv.FormatInt(f.Int(), 10), true
// add cases for more kinds as needed.
default:
return "", false
// or use fmt.Sprint(f.Interface())
}
}
- 1 回答
- 0 关注
- 214 浏览
添加回答
举报