python for循环随机

Question

lst = ['mylist1','mylist2','mylist3']for x in lst:    for r in xrange(2):        print x输出：（重复列表中的元素两次）[root@localhost ~]# python test.pymylist1mylist1mylist2mylist2mylist3mylist3如何随机元素到：mylist3mylist1mylist3mylist2mylist2mylist1

Answer 1

或*（乘法运算符）：

lst = lst*2 # repeat items twice

shuffle(lst)

for x in lst:

    print(x)

或者list comprehension：

lst = [x for i in range(2) for x in lst] # repeat items twice

shuffle(lst)

for x in lst:

    print(x)

Answer 2

您可以首先使用 list 将列表中的每个元素加倍extend()，然后对列表进行洗牌

from random import shuffle

lst = ['mylist1','mylist2','mylist3']

lst = lst.extend(lst) # repeat items twice

shuffle(lst)

for x in lst:

    print(x)