Python：从标准输入读取 gzip

Question

如何从标准输入中逐行读取压缩内容？我a.gz在当前目录中有一个包含 UTF-8 内容的 gzip 文件。场景一：使用gzip.open(filename)作品。我可以打印解压缩的线条。with gzip.open('a.gz', 'rt') as f:    for line in f:        print(line)# python3 my_script.py场景2：我想从标准输入读取 gzip 压缩的内容。所以我cat将 gzip 压缩文件作为以下脚本的输入。with gzip.open(sys.stdin, mode='rt') as f:    for line in f:        print(line)# cat a.gz | python3 script.py但是对于方法 2，我收到以下错误：Traceback (most recent call last):  File "script.py", line 71, in <module>    for line in f:  File "....../python3.6/gzip.py", line 289, in read1    return self._buffer.read1(size)  File "....../python3.6/_compression.py", line 68, in readinto    data = self.read(len(byte_view))  File "....../python3.6/gzip.py", line 463, in read    if not self._read_gzip_header():  File "....../python3.6/gzip.py", line 406, in _read_gzip_header    magic = self._fp.read(2)  File "....../python3.6/gzip.py", line 91, in read    self.file.read(size-self._length+read)  File "....../python3.6/codecs.py", line 321, in decode    (result, consumed) = self._buffer_decode(data, self.errors, final)UnicodeDecodeError: 'utf-8' codec can't decode byte 0x8b in position 1: invalid start byte

Answer 1

您想打开sys.stdin.buffer，而不是sys.stdin，因为后者透明地将字节解码为字符串。这对我有用：

with gzip.open(sys.stdin.buffer, mode='rt') as f:

    for line in f:

        print(line)