Scrapy 获取文本超出范围

Question

网址：https : //myanimelist.net/anime/236/Es_Otherwise我试图在 URL 中抓取以下内容：我试过了 ：for i in response.css('span[class = dark_text]') :    i.xpath('/following-sibling::text()')或者当前的 XPath 不起作用或者我错过了一些东西......aired_xpath = response.xpath('//*[@id="content"]/table/tbody/tr/td[1]/div/div[11]/text()')producer_xpath = response.xpath("//*[@id='content']/table/tbody/tr/td[1]/div/div[12]/span/a/@href/text()")licensor_xpath = response.xpath('//*[@id="content"]/table/tbody/tr/td[1]/div/div[13]/a/text()')studio_xpath response.xpath('//*[@id="content"]/table/tbody/tr/td[1]/div/div[14]/a/@href/title/text()')studio_xpath = response.xpath('//*[@id="content"]/table/tbody/tr/td[1]/div/div[17]/text()')str_rating_xpath = response.xpath('//*[@id="content"]/table/tbody/tr/td[1]/div/div[18]/text()')ranked_xpath = response.xpath('//*[@id="content"]/table/tbody/tr/td[1]/div/div[20]/span/text()')japanese_title_xpath = response.xpath('//*[@id="content"]/table/tbody/tr/td[1]/div/div[7]/text()')source_xpath = response.xpath('//*[@id="content"]/table/tbody/tr/td[1]/div/div[15]/text()')genre_xpath = [response.xpath('//*[@id="content"]/table/tbody/tr/td[1]/div/div[16]/a[{0}]'.format(i)) for i in range(1,4)]genre_xpath_v2 = response.xpath('//*[@id="content"]/table/tbody/tr/td[1]/div/div[16]/a/@href/text()')number_of_users_rated_anime_xpath = response.xpath('//*[@id="content"]/table/tbody/tr/td[1]/div/div[19]/span[3]/text()')popularity_xpath = response.xpath('//*[@id="content"]/table/tbody/tr/td[1]/div/div[21]/span/text()')members_xpath = response.xpath('//*[@id="content"]/table/tbody/tr/td[1]/div/div[22]/span/text()')favorite_xpath =  response.xpath('//*[@id="content"]/table/tbody/tr/td[1]/div/div[23]/span/text()')但我发现有些文本超出了跨度类，因此我想使用 css/XPath 公式使该文本超出跨度。

Answer 1

如果您只是想删除图像中提到的信息，则可以使用

response.xpath('//div[@class="space-it"]//text()').extract()

或者我无法正确理解您的问题。