m = [[1,2,3], [2,1,3], [5,4,3]]for i in range(len(m)): for j in range(len(m)*len(m)): if i <= len(m) and j <= (len(m)*len(m)): m[i][j] <= m[i+1][j+1] is_sink = "True" if i <= (len(m)-1) and j <= (len(m)*len(m)): m[i][j] <= m[i+1][j] is_sink = "True" if i <= len(m) and j <= ((len(m)*len(m))-1): m[i][j] <= m[i][j+1] is_sink = "True" if i <= (len(m)-1) and j <= (len(m)*len(m)): m[i][j] <= m[i+1][j-1] is_sink = "True" if i <= len(m) and j <= (len(m)*len(m)): m[i][j] <= m[i-1][j+1] is_sink = "True" if i <= len(m) and j <= (len(m)*len(m)): m[i][j] <= m[i][j-1] is_sink = "True" if i <= len(m) and j <= (len(m)*len(m)): m[i][j] <= m[i-1][j] is_sink = "True" else: is_sink = "False"我试图比较相邻的单元格以显示地图上的最低点。虽然它显示超出范围,但我不太确定如何正确表达范围。我确信这段代码可以减少,但这是我目前可以显示的最佳长度。
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