Python 将列表逐行分隔开

Question

我正在编写一个程序来做一些统计。我希望输出看起来像11: 422: 333: 1代替11:4, 22:3, 33:1因为我觉得很难读。这是我的代码#Copy solves here, in seconds, seperated by a comma for each solvetimes = [11.9, 14.2, 17.3, 11.2 , 123.4]#Blank list to copy modified solves intonewtimes = []for time in times:  #Rounds down every time  time = int(time)  #Adds time to new list  newtimes.append(time)#Sorts list lowest to highestnewtimes.sort()#Gets length of new list, which is amount of solvessolves = len(newtimes)#Set longest and shortest solve timeslongestSolve = max(newtimes)shortestSolve = min(newtimes)timesfreq = {i:newtimes.count(i) for i in newtimes}print(newtimes)print(timesfreq)print(solves)print("Your longest solve was " + str(longestSolve) + " seconds and your shortest solve was " + str(shortestSolve) + " seconds")

Answer 1

就这样：

for i in timesfreq.items():

    print(i)

这给

(11, 2)

(14, 1)

(17, 1)

(123, 1)

如果您完全按照您的说明想要它：

for a,b in timesfreq.items():

    print("{}: {}".format(a,b))

Answer 2

您可以将其作为单线执行的一种方法：

>>> print('\n'.join([str(key) + ': ' + str(val) for key, val in timesfreq.items()]))

123: 1

17: 1

11: 2

14: 1