我希望它在不是 0 或 1 时给我错误

Question

#!/usr/bin/pythondef open_doors(state):    (ld, rd, li, ri, lo, ro, cl, ml, gs) = state    if not(ld == 0 or rd == 0 or li == 0 or ri == 0 and lo == 0 or ro == 0 or cl == 0 or ml == 0):      raise ValueError("Error: A state is not specified or invalid entry")    if not(ld == 1 or rd == 1 or li == 1 or ri == 1 and lo == 1 or ro == 1 or cl == 1 or ml == 1):      raise ValueError("Error: A state is not specified or invalid entry")    leftDoor = (ld or li or lo)    rightDoor = (rd or ri or ro)    if (li and cl):      leftDoor = 0    if (ri and cl):      rightDoor = 0    if leftDoor and rightDoor and not ml and gs == 'P':      print("left door and right door open")    elif leftDoor and not ml and gs == 'P':      print("open left door")    elif rightDoor and not ml and gs == 'P':      print("open right door")    else:      print("both doors stay closed")   open_doors([0,0,1,6,0,0,1,0,'2'])如果未指定每个状态，开关和锁不是 0 或 1 或 gs 不是 ('P' 'R', 'N', '2', '3' 'D') 之一，则引发 ValueError

Answer 1

我会做

if any((i != 0 and i != 1) for i in state):

  raise ValueError("Error: A state is not specified or invalid entry")

这是简短而简洁的。

它甚至可以更改为

valid = set((0, 1))

if any(i not in valid for i in state):

  raise ValueError("Error: A state is not specified or invalid entry")

我不确定这是否是更好的性能或可读性。