在表面上绘制并使用 pygame 旋转

Question

我试图在 Python 中使用命令 context.rotate(angle) 在 JS 中模拟一些可用的行为。我有以下代码： import pygame import math import numpy as nppygame.init()CLOCK = pygame.time.Clock()RED = pygame.color.THECOLORS['red']WHITE = pygame.color.THECOLORS['white']screen = pygame.display.set_mode((0, 0), pygame.FULLSCREEN)screen_width, screen_height = screen.get_size()surface = pygame.Surface((50, 50), pygame.SRCALPHA)surface.fill((0, 0, 0))rotated_surface = surfacerect = surface.get_rect()ax = int(screen_width / 2)ay = int(screen_height / 2)angle = 0print("Size of the screen ({}, {})".format(screen_width, screen_height))print("Center of the screen ({}, {})".format(ax, ay))myfont = pygame.font.SysFont("monospace", 12)pygame.display.set_caption("Test rotate")main_loop = Trueamplifier = 200def calculate_angle(mouse_position):    dx = mouse_position[0] - ax    dy = mouse_position[1] - ay    return np.arctan2(dy,dx)while main_loop:    for event in pygame.event.get():        keys = pygame.key.get_pressed()        if event.type == pygame.QUIT or keys[pygame.K_ESCAPE]:            main_loop = False    pos = pygame.mouse.get_pos()    angle = (calculate_angle(pos) * 180)/math.pi    screen.fill((255,255,255))    rotated_surface = pygame.transform.rotate(surface, -angle)    rect = rotated_surface.get_rect(center = (ax, ay))    screen.blit(rotated_surface, (rect.x, rect.y))    pygame.draw.line(rotated_surface, WHITE, (ax,ay), (ax+20, ay), 1)    pygame.draw.line(rotated_surface, WHITE, (ax+10,ay-10), (ax+20, ay), 1)    pygame.draw.line(rotated_surface, WHITE, (ax+10,ay+10), (ax+20, ay), 1)    pygame.display.update()    CLOCK.tick(30)pygame.quit()我正在绘制一个箭头并希望根据鼠标在屏幕上的位置旋转它。我当然可以在每次进行一些正弦、余弦计算时重新绘制线条，但这很痛苦。我认为表面可以在这里帮助我，事实上，它适用于完美旋转的矩形。但是将我的线条画到表面上是行不通的。所以，我想我误解了表面的用途，或者我编码错误，有更好的方法来做到这一点。请注意，如果我在我的 draw.line 指令中用 screen 替换了 Rodated_surface，箭头确实会在屏幕上绘制，但永远不会旋转。有什么想法（除了使用图像/精灵；））？

Answer 1

问题是您在表面积外绘制箭头线。每个表面的左上角坐标为 (0, 0)，因此它们都有自己的（本地）坐标系。由于您使用屏幕的中心坐标来绘制线条，因此不会在可见表面区域中绘制箭头。

我会使用局部坐标在 while 循环之前的原始表面上绘制线条，然后旋转它并在循环内获得一个新的矩形。

import math

import pygame

pygame.init()

CLOCK = pygame.time.Clock()

GRAY = pygame.color.THECOLORS['gray50']

WHITE = pygame.color.THECOLORS['white']

screen = pygame.display.set_mode((800, 600))

screen_rect = screen.get_rect()  # A rect with the size of the screen.

surface = pygame.Surface((50, 50), pygame.SRCALPHA)

# surface.fill((0, 50, 150))  # Fill the surface to make it visible.

# Use the local coordinate system of the surface to draw the lines.

pygame.draw.line(surface, WHITE, (0, 0), (25, 0), 1)

pygame.draw.line(surface, WHITE, (0, 0), (25, 25), 1)

pygame.draw.line(surface, WHITE, (0, 0), (0, 25), 1)

# I rotate it so that the arrow is pointing to the right (0° is right).

surface = pygame.transform.rotate(surface, -135)

rect = surface.get_rect()

angle = 0

# If you're using Python 3.6+, you can use f-strings.

print(f"Size of the screen {screen.get_size()}")

print(f"Center of the screen {screen_rect.center}")

def calculate_angle(mouse_position):

    dx = mouse_position[0] - screen_rect.centerx

    dy = mouse_position[1] - screen_rect.centery

    return math.atan2(dy, dx)

main_loop = True

while main_loop:

    for event in pygame.event.get():

        # You shouldn't use `pygame.key.get_pressed` in the event loop.

        if (event.type == pygame.QUIT

            or event.type == pygame.KEYDOWN and event.key == pygame.K_ESCAPE):

            main_loop = False

    pos = pygame.mouse.get_pos()

    angle = math.degrees(calculate_angle(pos))

    screen.fill(GRAY)

    # Now just rotate the original surface and get a new rect.

    rotated_surface = pygame.transform.rotate(surface, -angle)

    rect = rotated_surface.get_rect(center=(screen_rect.center))

    screen.blit(rotated_surface, rect)

    pygame.display.update()

    CLOCK.tick(30)

pygame.quit()

我还尝试改进了一些其他内容（查看评论）。