在字典中寻找相似之处

Question

我试图找到多个 .txt 文件之间的相似之处。我已经把所有这些文件放在一个字典中，文件名作为关键字。当前代码：import pandas as pdfrom os import listdir, chdir, getcwdpath = (r'C:\...path')chdir(path)files = [f for f in listdir(path)]files_dict = {}for filename in files:    if filename.lower().endswith(('.txt')):        files_dict[str(filename)] = pd.read_csv(filename).to_dict('split')for key, value in files_dict.items():    print(key + str(value) +'\n')在这种情况下，关键是文件名。值是标题和数据。我想找出多个文件之间的值是否有重复，以便我可以在 SQL 中加入它们。我不知道该怎么做编辑示例文件：timestamp,Name,Description,Default Column Layout,Analysis View Name00000000B42852FA,ADM_EIG,Administratief eigenaar,ADM_EIG,ADM_EIG000000005880959E,OPZ,Opzeggingen,STANDAARD,并从代码：Acc_ Schedule Name.txt{'index': [0, 1], 'columns': ['timestamp', 'Name', 'Description', 'Default Column Layout', 'Analysis View Name'], 'data': [['00000000B42852FA', 'ADM_EIG', 'Administratief eigenaar', 'ADM_EIG', 'ADM_EIG'], ['000000005880959E', 'OPZ', 'Opzeggingen', 'STANDAARD', nan]]}编辑 2：建议的代码for key, value in files_dict.items():    data = value['data']    counter = Counter([item for sublist in data for item in sublist])    print([value for value, count in counter.items()])输出： ['00000000B99BD831', 5050, 'CK102', '0,00000000000000000000', 'Thuiswonend', 0, '00000000B99BD832', ........

Answer 1

该Counter数项的频率，所以会告诉你什么比这一次更出现。data从你的字典中取出：

from Collections import Counter

data = [

   ['00000000B42852FA', 'ADM_EIG', 'Administratiefeigenaar', 'ADM_EIG', 'ADM_EIG'],

   ['000000005880959E', 'OPZ', 'Opzeggingen', 'STANDAARD', nan]

]

您需要展平列表列表：

[item for sublist in data for item in sublist]

计数器将为您提供每个项目的频率：

>>> Counter([item for sublist in data for item in sublist])

Counter({'ADM_EIG': 3, '00000000B42852FA': 1, 'Administratief eigenaar': 1, '000000005880959E': 1, 'OPZ': 1, 'Opzeggingen': 1, 'STANDAARD': 1, nan: 1})

然后您可以过滤您需要的内容：

counter = Counter([item for sublist in data for item in sublist])

[value for value, count in counter.items() if count > 1]

这使 ['ADM_EIG']

编辑以匹配问题编辑

要查看所有行，请获取所有数据并查找重复项：

data = []

for key, value in files_dict.items():

    data.extend(value['data'])

counter = Counter([item for sublist in data for item in sublist])

print([value for value, count in counter.items() if count > 1])