我正在尝试按连续日期对 ID 进行分组。ID Date abc 2017-01-07 abc 2017-01-08 abc 2017-01-09 abc 2017-12-09 xyz 2017-01-05 xyz 2017-01-06 xyz 2017-04-15 xyz 2017-04-16 需要返回:ID Countabc 3abc 1xyz 2xyz 2我试过了:d = {'ID': ['abc', 'abc', 'abc', 'abc', 'xyz', 'xyz', 'xyz', 'xyz'], 'Date': ['2017-01-07','2017-01-08', '2017-01-09', '2017-12-09', '2017-01-05', '2017-01-06', '2017-04-15', '2017-04-16']}df = pd.DataFrame(data=d)df['Date'] = pd.to_datetime(df['Date'])today = pd.to_datetime('2018-10-23') x = df.sort_values('Date', ascending=0)g = x.groupby(['ID'])x[(today - x['Date']).dt.days == g.cumcount()].groupby(['ID']).size()是否有一种简单的方法可以通过 ID 获取所有日期范围的计数?
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