计算java字符串中的句子数

Question

我想计算一个字符串中的句子数，到目前为止我正在使用这个：int count = str.split("[!?.:]+").length;但我的字符串包含“。” 例如在名字和单词之间“他的名字是 Walton DC，他去年刚刚完成了他的 B.Tech。”现在使用上面的行作为示例 count 将返回 4 个句子，但只有一个。那么如何应对这些情况呢？

Answer 1

您可以使用BreakIterator，并检测不同类型的文本边界

在你的情况下句子：

private static void markBoundaries(String target, BreakIterator iterator) {

    StringBuffer markers = new StringBuffer();

    markers.setLength(target.length() + 1);

    for (int k = 0; k < markers.length(); k++) {

        markers.setCharAt(k, ' ');

    }

    int count = 0;

    iterator.setText(target);

    int boundary = iterator.first();

    while (boundary != BreakIterator.DONE) {

        markers.setCharAt(boundary, '^');

        ++count;

        boundary = iterator.next();

    }

    System.out.println(target);

    System.out.println(markers);

    System.out.println("Number of Boundaries: " + count);

    System.out.println("Number of Sentences: " + (count-1));

}

public static void main(String[] args) {

    Locale currentLocale = new Locale("en", "US");

    BreakIterator sentenceIterator

            = BreakIterator.getSentenceInstance(currentLocale);

    String someText = "He name is Walton D.C. and he just completed his B.Tech last year.";

    markBoundaries(someText, sentenceIterator);

    someText = "This order was placed for QT3000! MK?";

    markBoundaries(someText, sentenceIterator);

}

输出将是：

He name is Walton D.C. and he just completed his B.Tech last year.

^                                                                 ^

Number of Boundaries: 2

Number of Sentences: 1

This order was placed for QT3000! MK?

^                                 ^  ^

Number of Boundaries: 3

Number of Sentences: 2

Answer 2

解决方案可能是在点的情况下，您可以检查后面是否有空格和大写字母。

“[点][空格][大写字母]”

这将是对判决的肯定

更新相同的代码：

public static void main( String args[] ) {

      // String to be scanned to find the pattern.

      String line = "This order was placed for QT3000! MK? \n Thats amazing. \n But I am not sure.";

  String pattern = "([.!?])([\\s\\n])([A-Z]*)";

  // Create a Pattern object

  Pattern r = Pattern.compile(pattern);

  // Now create matcher object.

  Matcher m = r.matcher(line);

  int count=0;

  while (m.find( )) {

      count++;

  }

  count++; //for the last line, which will not get included here.

  System.out.println("COUNT=="+count);

}

Answer 3

简单的方法

公共类计数线{

public static void main(String[] args) {

    // TODO Auto-generated method stub

    String s="Find the number Sentence";

    int count=0;

    for (int i = 0; i < s.length(); i++) {

        if(s.charAt(i)==' ') {

            count++;

        }

    }

    count=count+1;

    System.out.println(count);

}

}