将字典中的所有列表相互比较

Question

在python中是否可以比较以下结构中的所有对象我有一个列表字典，每个列表中都有对象，例如[      [object1,object2,object3],      [object4,object5,object6],      [object7,object8,object9],]我想通过每个列表中的属性将所有对象相互比较，并确定每个列表中没有哪些对象。根据反馈，请参阅下面的示例from collections import defaultdictfrom pprint import pprintclass mytest:  def __init__(self, no, description):    self.no = no    self.description = descriptiondata = []x = mytest(1,'test1')x2 = mytest(2,'test1')x3 = mytest(1,'test2')x4 = mytest(2,'test2')x5 = mytest(3,'test2')x6 = mytest(1,'test3')x7 = mytest(2,'test3')x8 = mytest(4,'test3')data.append(x)data.append(x2)data.append(x3)data.append(x4)data.append(x5)data.append(x6)data.append(x7)data.append(x8)groups = defaultdict(list)for obj in data:    groups[obj.description].append(obj)new_list = groups.values()#i want to find out what items are not in each listfor list in new_list:    pprint(list)#example x8 = mytest(4,'test3') is only in one of the list so is missing from list 1 and 2希望这会有所帮助