python - 是否可以使用特定数字比较两个列表之间的列表？

Question

我是一个正在学习用 python 编程的新学生，我有 2 个示例列表，它们是selected_ipc = ['H01L']df = [[ 'F24J3/02 ', 'A123'], [ 'G01N31/10 ', 'A124'], [ 'H01L27/14 ', 'A125'], ['G21H1/10 ', 'A126'], ['H01L21/36 ', 'A127']]我创建了一个像这样的简单代码for item in selected_ipc:    for item1 in df:        if item == item1:            print (item)        else:            print("No match")结果返回“不匹配”，而我的预期结果是[[ 'H01L27/14 ', 'A125'], ['H01L21/36 ', 'A127']]因此，我想问一下，是否可以将第一个列表与第二个列表中的前 4 位数字进行比较？先感谢您

Answer 1

您可以使用startswith：

selected_ipc = ['H01L']

df = ['F24J3/02 ', 'G01N31/10 ', 'H01L27/14 ', 'G21H1/10 ', 'H01L21/36 ']

for item in selected_ipc:

    for item1 in df:

        if item1.startswith(item):

            print(item1)

        else:

            print("No match")

输出

No match

No match

H01L27/14 

No match

H01L21/36 

更新

对于嵌套列表，您可以使用列表理解：

selected_ipc = ['H01L']

df = [['F24J3/02 ', 'A123'], ['G01N31/10 ', 'A124'], ['H01L27/14 ', 'A125'], ['G21H1/10 ', 'A126'],

      ['H01L21/36 ', 'A127']]

result = [lst for lst in df if any(lst[0].startswith(e) for e in selected_ipc)]

print(result)

输出

[['H01L27/14 ', 'A125'], ['H01L21/36 ', 'A127']]

作为替代方案，您可以使用带有两个循环的较少Pythonic 的方式：

selected_ipc = ['H01L']

df = [['F24J3/02 ', 'A123'], ['G01N31/10 ', 'A124'], ['H01L27/14 ', 'A125'], ['G21H1/10 ', 'A126'],

      ['H01L21/36 ', 'A127']]

result = []

for lst in df:

    found = False

    for e in selected_ipc:

        if lst[0].startswith(e):

            found = True

            result.append(lst)

            break

    if not found:

        print("No match")

print(result)

输出

No match

No match

No match

[['H01L27/14 ', 'A125'], ['H01L21/36 ', 'A127']]

Answer 2

你可以用下面的列表理解来做到这一点

selected_ipc = ['H01L']

df = ['F24J3/02 ', 'G01N31/10 ', 'H01L27/14 ', 'G21H1/10 ', 'H01L21/36 ']

for item in selected_ipc:

    match_lst = [item1 for item1 in df if item in item1]

print(match_lst)

更新

如果要检查列表“df”中列表的其他元素（而不是第一个），则可以查看以下代码

selected_ipc = ['H01L', 'G01N', 'A126']

df = [['F24J3/02 ', 'A123'], ['G01N31/10 ', 'A124'], ['H01L27/14 ', 'A125'], ['G21H1/10 ', 'A126'],

      ['H01L21/36 ', 'A127']]

match_lst = [item1 for item1 in df if any(i.startswith(item) for item in selected_ipc for i in item1)]

print(match_lst)

输出

[['G01N31/10 ', 'A124'], ['H01L27/14 ', 'A125'], ['G21H1/10 ', 'A126'], ['H01L21/36 ', 'A127']] 

Answer 3

selected_ipc = ['H01L']

df = ['F24J3/02 ', 'G01N31/10 ', 'H01L27/14 ', 'G21H1/10 ', 'H01L21/36 ']

l = []

for i in df:

   if selected_ipc[0] in i:

       l.append(i)

print l