数据不正确时的Java showInputDialog

Question

import javax.swing.*;import java.io.Serializable;import java.rmi.registry.LocateRegistry;import java.rmi.registry.Registry;public class Server implements Serializable{    public static void main(String[] args) {        String test1= JOptionPane.showInputDialog(null,"Port(0-65535):","Port",JOptionPane.QUESTION_MESSAGE);        int portnumber = tryParse(test1);        if (portnumber !=0) {            try {                Registry reg = LocateRegistry.createRegistry(portnumber);   //Creates and exports a Registry instance on the local host that accepts requests                RmiImplementation imp = new RmiImplementation("C://ServerStorage");                reg.bind("remoteObject", imp);                System.out.println("Server is ready.");                System.out.println(portnumber);            } catch (Exception e) {                System.out.println("Server failed: " + e);            }        }    }    private static Integer tryParse(String text) {        try {            return Integer.parseInt(text);        } catch (Exception e) {            return 0;        }    }}上面的代码帮助我设置我的文件服务器。当应用程序运行时，会请求对话框端口号。如果我输入字母而不是数字，程序将停止运行，但我希望它继续并再次显示对话框。

Answer 1

尝试使用do-while,

int portnumber = 0;

do {

     String text= JOptionPane.showInputDialog(null,"Port(0-65535):","Port",JOptionPane.QUESTION_MESSAGE);

     portnumber = tryParse(text);

}while(portnumber==0);