我正在使用 Retrofit 来获取数据并将其显示到屏幕上。我想通过他们的 id 搜索用户。我做了这样的界面: @GET("/posts/{id}")Call<postmodel> getUsersModel(@Path("id") int id);问题出在 DetailActivity 第 52 行: EndPointAccess access = APIClient.getRetrofit().create(EndPointAccess.class); Call<postmodel> modelCall = access.getUsersModel(Integer.parseInt(_userinput));这是 Logcat 报告:android.content.res.Resources$NotFoundException: String resource ID #0x1atandroid.content.res.Resources.getText(Resources.java:351)atandroid.content.res.MiuiResources.getText(MiuiResources.java:97)atandroid.widget.TextView.setText(TextView.java:4562)at com.example.sahil.typicode1.Activity.DetailActivity$2.onResponse(DetailActivity.java:60)API客户端.java public static final String BASE_URL = "https://jsonplaceholder.typicode.com";private static Retrofit retrofit = null;public static Retrofit getRetrofit(){ if (retrofit == null) { retrofit = new Retrofit.Builder().baseUrl(BASE_URL) .addConverterFactory(GsonConverterFactory .create()).build(); } return retrofit;}EndPointAccess.java(接口) @GET("/posts/{id}")Call<postmodel> getUsersModel(@Path("id") int id);主活动.javaEditText userid;Button search;@Overrideprotected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_main); userid = (EditText) findViewById(R.id.etuserid); search = (Button) findViewById(R.id.btnsearch); search.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View view) { Intent intent = new Intent(MainActivity.this,DetailActivity.class); intent.putExtra("STRING_I_NEED",userid.getText().toString()); startActivity(intent); } });}
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