如何解决属性错误“float”对象在python中没有属性“split”？

Question

当我运行下面的代码时，它给我一个错误，说存在属性错误：'float' object has no attribute 'split' in python。我想知道为什么会出现这个错误。def text_processing(df):    """""=== Lower case ==="""    '''First step is to transform comments into lower case'''    df['content'] = df['content'].apply(lambda x: " ".join(x.lower() for x in x.split() if x not in stop_words))    return dfdf = text_processing(df)错误的完整回溯：Traceback (most recent call last):  File "C:\Program Files\JetBrains\PyCharm Community Edition 2018.2.2\helpers\pydev\pydevd.py", line 1664, in <module>    main()  File "C:\Program Files\JetBrains\PyCharm Community Edition 2018.2.2\helpers\pydev\pydevd.py", line 1658, in main    globals = debugger.run(setup['file'], None, None, is_module)  File "C:\Program Files\JetBrains\PyCharm Community Edition 2018.2.2\helpers\pydev\pydevd.py", line 1068, in run    pydev_imports.execfile(file, globals, locals)  # execute the script  File "C:\Program Files\JetBrains\PyCharm Community Edition 2018.2.2\helpers\pydev\_pydev_imps\_pydev_execfile.py", line 18, in execfile    exec(compile(contents+"\n", file, 'exec'), glob, loc)  File "C:/Users/L31307/Documents/FYP P3_Lynn_161015H/FYP 10.10.18 (Wed) still working on it/FYP/dataanalysis/category_analysis.py", line 53, in <module>    df = text_processing(df)  File "C:/Users/L31307/Documents/FYP P3_Lynn_161015H/FYP 10.10.18 (Wed) still working on it/FYP/dataanalysis/category_analysis.py", line 30, in text_processing    df['content'] = df['content'].apply(lambda x: " ".join(x.lower() for x in x.split() if x not in stop_words))  File "C:\Users\L31307\AppData\Roaming\Python\Python37\site-packages\pandas\core\series.py", line 3194, in apply

Answer 1

错误指向这一行：

df['content'] = df['content'].apply(lambda x: " ".join(x.lower() for x in x.split() \

                                    if x not in stop_words))

split这里用作 Python 内置str类的方法。您的错误表明中的一个或多个值df['content']的类型为float。这可能是因为存在空值，即NaN，或非空浮点值。

一个解决办法，这将字符串化浮动，是只适用str于x使用前split：

df['content'] = df['content'].apply(lambda x: " ".join(x.lower() for x in str(x).split() \

                                    if x not in stop_words))

或者，可能是更好的解决方案，明确并使用带有try/except子句的命名函数：

def converter(x):

    try:

        return ' '.join([x.lower() for x in str(x).split() if x not in stop_words])

    except AttributeError:

        return None  # or some other value

df['content'] = df['content'].apply(converter)

由于pd.Series.apply只是一个有开销的循环，您可能会发现列表理解或map更有效：

df['content'] = [converter(x) for x in df['content']]

df['content'] = list(map(converter, df['content']))

Answer 2

split() 是一种仅适用于字符串的 Python 方法。似乎您的“内容”列不仅包含字符串，还包含其他值，例如无法应用 .split() 方法的浮点数。

尝试使用 str(x).split() 将值转换为字符串，或者首先将整个列转换为字符串，这样效率会更高。您按如下方式执行此操作：

df['column_name'].astype(str)