Python：分隔列表中的术语并赋值

Question

我使用了关键字提取器并获得了如下列表-[('solutions design team', 0.5027793039863974), ('communication skills', 0.039048703166463736), ('internal stakeholders', 0.03230578820017667),('potential customers', 0.020380881551651655), ('utilize', 0.002776174060064261)]我试图将这些单词中的每一个分开，并分别为每个单词分配相应的值（在右侧给出）。例如-将“解决方案设计团队”= 0.5027793039863974 转换为'solutions' = 0.5027793039863974, 'design' = 0.5027793039863974 ,   'team' = 0.5027793039863974.

Answer 1

如何使用双重平面理解重新创建一个带有分隔词的元组列表：

inlist = [('solutions design team', 0.5027793039863974),

('communication skills', 0.039048703166463736),

('internal stakeholders', 0.03230578820017667),

('potential customers', 0.020380881551651655), ('utilize', 0.002776174060064261)]

outlist = [(word,value) for words,value in inlist for word in words.split()]

结果：

>>> outlist

[('solutions', 0.5027793039863974),

 ('design', 0.5027793039863974),

 ('team', 0.5027793039863974),

 ('communication', 0.039048703166463736),

 ('skills', 0.039048703166463736),

 ('internal', 0.03230578820017667),

 ('stakeholders', 0.03230578820017667),

 ('potential', 0.020380881551651655),

 ('customers', 0.020380881551651655),

 ('utilize', 0.002776174060064261)]

请注意，如果关键字出现多次，则元组列表中将出现重复项。如果你想累积它们，一个collections.defaultdict(float)对象可以很方便地创建一个带有关键字=>累积值的字典。

accumulated = collections.defaultdict(float)

for word,value in outlist:

    accumulated[word] += value

Answer 2

字典理解，字典更新可以通过以下方式帮助您

corpus = [('solutions design team', 0.5027793039863974), ('communication skills', 0.039048703166463736), ('internal stakeholders', 0.03230578820017667), ('potential customers', 0.020380881551651655), ('utilize', 0.002776174060064261)]

final_dict = {}

for phase, prob in corpus:

    final_dict.update({word:prob for word in phase.split()}

print(final_dict['solutions'])

print(final_dict['design'])