3 回答
TA贡献1840条经验 获得超5个赞
用
fmt.Println(t.Format("20060102150405"))
由于 Go 使用以下常量来格式化日期,请参阅此处
const (
stdLongMonth = "January"
stdMonth = "Jan"
stdNumMonth = "1"
stdZeroMonth = "01"
stdLongWeekDay = "Monday"
stdWeekDay = "Mon"
stdDay = "2"
stdUnderDay = "_2"
stdZeroDay = "02"
stdHour = "15"
stdHour12 = "3"
stdZeroHour12 = "03"
stdMinute = "4"
stdZeroMinute = "04"
stdSecond = "5"
stdZeroSecond = "05"
stdLongYear = "2006"
stdYear = "06"
stdPM = "PM"
stdpm = "pm"
stdTZ = "MST"
stdISO8601TZ = "Z0700" // prints Z for UTC
stdISO8601ColonTZ = "Z07:00" // prints Z for UTC
stdNumTZ = "-0700" // always numeric
stdNumShortTZ = "-07" // always numeric
stdNumColonTZ = "-07:00" // always numeric
)
TA贡献1808条经验 获得超4个赞
import("time")
layout := "2006-01-02T15:04:05.000Z"
str := "2014-11-12T11:45:26.371Z"
t, err := time.Parse(layout, str)
if err != nil {
fmt.Println(err)
}
fmt.Println(t)
给出:
>> 2014-11-12 11:45:26.371 +0000 UTC
- 3 回答
- 0 关注
- 348 浏览
添加回答
举报