如何删除元组列表中的重叠元素？

Question

我有一个元组列表[('one','two','three'),('four','five','six'),('seven','eight','nine')]和一个清单['three','five','nine']我想要做的是删除与第二个清单，这样我就有了[('one','two'),('four','six'),('seven','eight')]有没有一种简单的方法可以做到这一点？

Answer 1

listoflists = [('one','two','three'),('four','five','six'),('seven','eight','nine')]

toremove = ['three','five','nine']

outcome = [tuple(item for item in list if item not in toremove) for list in listoflists]

Answer 2

创建一个新的元组列表

a=[('one','two','three'),('four','five','six'),('seven','eight','nine')]

b=['three','five','nine']

[set(i).difference(b) for i in a] # if you do not care about the order inside the tuple