我想要所需的输出 -coord = {0: (0, 0), 1: (0, 1), 2: (0, 2), 3: (0, 3),4: (1, 0), 5: (1, 1), 6: (1, 2),7: (1, 3),8: (2, 0), 9: (2, 1), 10: (2, 2),11: (2, 3),12: (3, 0), 13: (3, 1), 14: (3, 2), 15: (3, 3)}使用coord = {}for i in range(0,16): if i < 4: for j in range (0,4): coord[i] = (0,j) elif i > 3 and i <8: for j in range (0,4): coord[i] = (1,j) elif i > 7 and i < 12: for j in range (0,4): coord[i] = (1,j) elif i > 11 and i < 16: for j in range (0,4): coord[i] = (1,j)print (coord)得到输出为 {0: (0, 3), 1: (0, 3), 2: (0, 3), 3: (0, 3), 4: (1, 3), 5: (1, 3), 6: (1, 3), 7: (1, 3), 8: (1, 3), 9: (1, 3), 10: (1, 3), 11: (1, 3), 12: (1, 3), 13: (1, 3), 14: (1, 3), 15: (1, 3)}无法构建逻辑以获得所需的输出。
2 回答

慕姐4208626
TA贡献1852条经验 获得超7个赞
最直接的方法是使用嵌套的 for 循环。
k = 0
d = {}
for i in range(4):
for j in range(4):
d[k] = (i, j)
k += 1
或者,如果您更喜欢 oneliners,则双重理解
dict( enumerate ( [ (i, j) for i in range(4) for j in range(4)] ))
要获得一个简单的 for 循环或推导式,我们可以使用整数算术运算符 //(整数除法)和 % 余数
{ k : (k // 4, k % 4) for k in range(16) }
这可能更优雅和快速

HUX布斯
TA贡献1876条经验 获得超6个赞
我们可以枚举整数的笛卡尔积itertools.product。
import itertools as it
{i: x for i, x in enumerate(it.product(range(3+1), repeat=2))}
# {0: (0, 0),
# 1: (0, 1),
# 2: (0, 2),
# 3: (0, 3),
# ...
# 15: (3, 3)}
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