Java - 识别最后一个具有特殊字符的字符串

Question

在迭代时有一个字符串列表，我试图识别包含任何特殊字符的字符串的最后一个字符。例如：Apple,AppleApple(Apples.Apples预期结果 ：AppleApples请在下面找到我的代码，到目前为止，我只是用“”（空）替换了特殊字符。，但我想删除字符串本身。for (TermSuggestion.Entry entry : termSuggestion.getEntries()) {     for (TermSuggestion.Entry.Option option : entry) {         String suggestText = option.getText().string();        String result = suggestText.replaceAll("[-+.^:,]()","");        System.out.println("Print String--->  "+result);    }}

Answer 1

您可以使用Character.isAlphabetic它来确定它是否是特殊字符。您可以使用String.charAt获取最后一个字符。

for (TermSuggestion.Entry entry : termSuggestion.getEntries())

{ 

    for (TermSuggestion.Entry.Option option : entry)

    { 

        String suggestText = option.getText().string();

        if (Character.isAlphabetic(suggestText.charAt(suggestText.length()))

        {

            System.out.println("Print String--->  "+result);

        }

    }

}

Answer 2

以下代码与 Streams 和 apache.commons.lang3。

List<String> strings = Arrays.asList("Apple", "Apple", "Apple", "Apples.", "Apples");

String[] alphabet = {"a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m", "n", "o", "p", "q", "r", "s", "t", "u", "v", "w", "x", "y", "z"};

List<String> result = strings.stream().filter(item -> StringUtils.endsWithAny(item, alphabet)).distinct().collect(Collectors.toList());

Answer 3

您可以使用此正则表达式.*[a-z]$仅过滤以小写/小写字符结尾的单词。