Python：捕获 logging.exception() 调用

Question

我试图捕捉一个没有引发的异常，只是记录了。有没有办法做到这一点？def exampleFunction():    try:        x = 1 / 0    except Exception:        logging.exception('divide by 0 error here.')try:    exampleFunction()except <condition based on if logging.exception was called>    print('there was a divide by 0 error when I called exampleFunction()')

Answer 1

我假设 exampleFunction 位于您不拥有的一些可怕的第三方代码中，否则有很多更好的选择。

你可以做什么：

import logging # make sure this is the FIRST import of logging

import horrible_third_party_lib

def catch_log(msg):

   # do something when this is called

old_logging = logging.exception

try:

    logging.exception=catch_log

    horrible_third_party_lib.exampleFunction()

finally:

    logging.exception=old_logging

然后，您可以在函数中执行任何您想做的事情。它对导入顺序既可怕又敏感，但我已经使用了它并且它有效（scikit learn 做了类似令人反感的事情......）

Answer 2

问题：我正在尝试捕获异常

问题标题应重写为“我正在尝试重新引发异常”

阅读Python 文档

#raise 似乎有点双重工作，但你可以这样做：

def exampleFunction():

    try:

        x = 1 / 0

    except Exception as e:

        print("logging.exception({})".format(e))

        raise

try:

    exampleFunction()

except ZeroDivisionError as e:

    print('there was a divide by 0 error when I called exampleFunction()')

输出：

logging.exception(division by zero)

there was a divide by 0 error when I called exampleFunction()

用 Python 测试：3.5.3