如何从目录列表中读取文件？

Question

这里我有很多耐心折叠，每个折叠有 10 个图像。我有一个列表，其中存储了我想要的一些目录。如何仅从列表（data_paths）上的目录加载/读取文件？# data_paths is the listdata_paths = ['./data/preprocessed_data/train/Patient009969', './data/preprocessed_data/train/Patient009928', './data/preprocessed_data/train/Patient009966'] data_and_seg_arr = [np.load(ii, mmap_mode='r') for ii in data_paths]Eror:IsADirectoryError: [Errno 21] Is a directory: './data/preprocessed_data/train/Patient009969'我需要保留这个数据表格。因为我将不得不这样做：pids = [ii.split('/')[-1].split('.')[0] for ii in data_paths]data = OrderedDict()for ix, pid in enumerate(pids):    data[pid] = {'data': data_and_seg_arr[ix][..., 0], 'seg': data_and_seg_arr[ix][..., 1], 'pid': pid}return data

Answer 1

假设所有文件都是 jpg 或 png 格式

path="/path/to/image"

#NOTE THIS IS REALLY IMPORTANT

#IF YOUR PATH IS LIKE THIS /path/to/image YOU NEED TO ADD A / AT THE END, IF 

#YOUR PATH ALREADY HAVE THE "/" AT THE END YOU DON'T NEED TO ADD IF

#EXAMPLE PROBLEM PATH:/path/to/image

#PATH WITH NO PROBLEM /path/to/image/

jpg = glob.glob(path + "/*.jpg")

png = glob.glob(path + "/*.png")

imagelist=jpg+png

>>>print(type(imagelist))

<class 'list'>

希望这能解决您的问题

Answer 2

您需要创建另一个循环，遍历路径列表中的文件。

import os

for path in data_paths:

      for file in os.listdir(path):

             data_and_seg_arr = [np.load(file, ...