所以我的代码在下面，它从 dmgeqdelete.php 读取，它将立即从数据库中删除数据。 <td align="center"><a href="dmgeqdelete.php?damagedID=<?php echo $row["damagedID"]; ?>" >Delete</a></td>我试图为上面的代码添加一个弹出确认。我试过<td align="center"><a href="dmgeqdelete.php?damagedID=<?php echo $row["damagedID"]; ?>" onclick="return confirm('Are you sure?')">Delete</a></td>最终没有任何动作发生dmgeqdelete.php<?phpinclude('dbConfig.php');$damagedID=$_REQUEST['damagedID'];$query = "DELETE FROM damagedeq WHERE damagedID=$damagedID"; $result = mysqli_query($conn,$query) or die ( mysqli_error());header("Location: dmgeqview.php"); ?>所以我的代码在下面，它从 dmgeqdelete.php 读取，它将立即从数据库中删除数据。 <td align="center"><a href="dmgeqdelete.php?damagedID=<?php echo $row["damagedID"]; ?>" >Delete</a></td>我试图为上面的代码添加一个弹出确认。我试过<td align="center"><a href="dmgeqdelete.php?damagedID=<?php echo $row["damagedID"]; ?>" onclick="return confirm('Are you sure?')">Delete</a></td>最终没有任何动作发生dmgeqdelete.php<?phpinclude('dbConfig.php');$damagedID=$_REQUEST['damagedID'];$query = "DELETE FROM damagedeq WHERE damagedID=$damagedID"; $result = mysqli_query($conn,$query) or die ( mysqli_error());header("Location: dmgeqview.php"); ?>展开片段完整代码<?phpinclude('dbConfig.php');?><!DOCTYPE html><html><head> <meta charset="utf-8"> <title>View Damaged Equipment Records</title> <link rel="stylesheet" href="css/style.css" /></head><body> <div class="form"> <p><a href="report.php">Home</a> | <a href="index.php">Logout</a></p> <h2>View Records</h2> <table width="100%" border="1" style="border-collapse:collapse;"> <thead> <tr> <th><strong>No</strong></th> <th><strong>Damage ID's</strong></th> <th><strong>EQ ID's</strong></th> <th><strong>Student ID's</strong></th> <th><strong>Staff ID's</strong></th> <th><strong>Date reported</strong></th> /tr> <?php $count++; } ?> </tbody> </table> </div></body></html>
1 回答
- 1 回答
- 0 关注
- 166 浏览
添加回答
举报
0/150
提交
取消