在 python 中添加两次需要帮助/反馈

Question

我目前正在开发一个关于时钟算法的程序。我的程序要求用户提供两个不同的时间，标准格式和军用时间 [HH:MM:SS]。然后我将这两次加在一起得到我的最终结果。我需要帮助解决我试图解决的两个问题，但我一直在努力解决。最后应该是这样的： HH:MM:SS + HH:MM:SS = HH:MM:SS 结果完全取决于用户输入的内容您能告诉我一种方法可以防止时间超过/超过 24 小时 60 分 60 秒吗？这些是截止时间，如果小时、分钟或秒超过了它们的截止时间，则总和时间将毫无意义。我想知道如何做到这一点，我在想它需要整数除法或模运算符 (%)。我将不胜感激您的帮助。我需要将我的时间保持在这些界限内，因为用户可以选择任何可能溢出的时间。在达到这些截止点后，时间应该重新开始归零并从那里开始。如何确保我的最终时间保持在 [HH:MM:SS] 格式？我将不胜感激您对此的帮助。有时，格式会显示为 [H:M:S]，这是我不想要的。我将非常感谢您对我正在努力解决的这两个问题的帮助。我非常接近一切正常。我只需要知道让我的时间在达到某个限制后重新开始的代码，以及一种保持 [HH:MM:SS] 格式的方法。我的程序代码如下所示。太感谢了，代码ClockTime1 = input('Enter clock two timie (in military time) in the format HH:MM:SS , it has to be in this format in order to function correctly :')ClockTime2= input('Enter clock one time (in military time) in the format HH:MM:SS , it has to be in this format in order to function correctly :')print(ClockTime1.split(':'))print(ClockTime2.split(':'))ClockTime1Hours= int((ClockTime1.split(':')[0]))ClockTime2Hours= int((ClockTime2.split(':')[0]))ClockTime2Minutes= int((ClockTime2.split(':')[1]))ClockTime1Seconds= int((ClockTime1.split(':')[2]))ClockTime2Seconds= int((ClockTime2.split(':')[2]))print(ClockTime1Hours,'hours for clock 1')print(ClockTime2Hours,'hours for clock 2')print(ClockTime1Minutes,'minutes for clock 1')print(ClockTime2Minutes,'minutes for clock 2')print(ClockTime1Seconds,'seconds for clock 1')print(ClockTime2Seconds,'seconds for clock 2')ClockTime1Hours += ClockTime2Hoursprint('sum of clock hours=',ClockTime1Hours)ClockTime1Minutes += ClockTime2Minutesprint('sum of clock minutes=',ClockTime1Minutes)ClockTime1Seconds += ClockTime2Secondsprint('sum of clock seconds=',ClockTime1Seconds)

Answer 1

我认为 python 时间模块可以提供帮助

import time

a = "00:00:00 1971"

a = time.mktime(time.strptime(a,"%H:%M:%S %Y"))

ClockTime1 = input('Enter clock two timie (in military time) in the format HH:MM:SS , 

it has to be in this format in order to function correctly :')

ClockTime2= input('Enter clock one time (in military time) in the format HH:MM:SS , 

it has to be in this format in order to function correctly :')

ClockTime1+=" 1971"

ClockTime2+=" 1971"

ClockTime1 = time.mktime(time.strptime(ClockTime1,"%H:%M:%S %Y"))

ClockTime2 = time.mktime(time.strptime(ClockTime2,"%H:%M:%S %Y"))

print(time.strftime("%H:%M:%S", time.localtime(ClockTime1-a+ClockTime2-a+a)))

Answer 2

我认为我们可以使用一些内置的日期时间函数，而不是自己计算它们：

from datetime import datetime,timedelta

str_t1="23:00:01"

str_t2="23:00:01"

dt1 = datetime.strptime(str_t1, '%H:%M:%S')

dt2 = datetime.strptime(str_t2, '%H:%M:%S')

dt2_delta=timedelta(hours=dt2.hour, minutes=dt2.minute, seconds=dt2.second)

dt3=dt1+dt2_delta

str_t3=datetime.strftime(dt3,'%H:%M:%S')

str_t3 的输出是：

str_t3 '22:00:02'