我在这里有一个登录页面，其中有两个字段和一个提交按钮。代码看起来不错，但是当我按下提交按钮时，没有任何内容传递给 isset 方法。这是我的代码。<?phpfunction security($database,$value){ $new_val=stripslashes($value); $new_val=mysqli_real_escape_string($database,$value); return $new_val;}require_once("database.php");if(isset($_POST['submit'])){ echo "working"; $username=security("betit",$_POST['username']); $paassword=security("betit",$_POST['password']); $sql="SELECT * FROM user_info WHERE username='$username' and password='$password'"; $result=mysqli_query("betit",$sql); if($result) { echo "congrats"; } }?><!DOCTYPE html><html><head> <title>LOGIN</title> <meta charset="utf-8"> <meta name="viewport" content="width=device-width, initial-scale=1"> <link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.4.0/css/bootstrap.min.css"> <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.4.0/jquery.min.js"></script> <script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.4.0/js/bootstrap.min.js"></script></head><body><div class="container"> <div class="row"> <h3>Login</h3> <div class="col-3"> <form method="post" action="" > <div class="input-group"> <span class="input-group-addon"><i class="glyphicon glyphicon-user"></i></span> <input id="email" type="text" class="form-control" name="username" placeholder="Username"> </div> <div class="input-group"> <span class="input-group-addon"><i class="glyphicon glyphicon-lock"></i></span> <input id="password" type="password" class="form-control" name="password" placeholder="Password"> </div> <input type="button" class="btn btn-primary" name="submit" value="submit"> </form> </div> </div></div></body></html>数据库.php<?phpfunction db_connection($hostname, $username, $password, $database){$link = mysqli_connect($hostname, $username, $password, $database);if($link === false){ die("ERROR: Could not connect. " . mysqli_connect_error());}提交按钮应该调用 isset 方法，但没有通过。我只是无法确定它是什么类型的错误。
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