从存储在两个数据框中的两个数据透视表中减去值

Question

我有两个表：df1:[1 rows x 23 columns]                 1C   1E    1F    1H    1K ...    2M    2P    2S  2U   2Wtotal          1057  334  3609  3762  1393 ...   328  1611  1426  87  118df2:[1 rows x 137 columns]                 1CA  1CB  1CC  1CF  1CJ  1CS ...   2UB  2UJ  2WB  2WC  2WF  2WJtotal            11  381  111   20  527    2 ...    47   34   79    2    1   36我需要减去两个表之间的值。像1C-1CF，1E-1EF，1F-1FF等等。即我只需要减去F以 sheet2结尾的列。Answer: 1C=1C-1CF=1037这怎么可能使用 Python 代码？笔记：一些“df1”在“df2”中没有“F”df1:['1C', '1E', '1F', '1H', '1K', '1M', '1N', '1P', '1Q', '1R', '1S', '1U', '1W', '2C', '2E', '2F', '2H', '2K', '2M', '2P', '2S', '2U', '2W']df2:['1CA', '1CB', '1CC', '1CF', '1CJ', '1CS', '1CU', '1EA', '1EB', '1EC', '1EF', '1EJ', '1ES', '1FA', '1FB', '1FC', '1FF', '1FJ', '1FS', '1FT', '1FU', '1HA', '1HB', '1HC', '1HF', '1HJ', '1HS', '1HT', '1HU', '1KA', '1KB', '1KC', '1KF', '1KJ', '1KS', '1KU', '1MA', '1MB', '1MC', '1MF', '1MJ', '1MS', '1MU', '1NA', '1NB', '1NC', '1NF', '1NJ', '1PA', '1PB', '1PC', '1PF', '1PJ', '1PS', '1PT', '1PU', '1QA', '1QB', '1QC', '1QF', '1QJ', '1RA', '1RB', '1RC', '1RF', '1RJ', '1SA', '1SB', '1SC', '1SF', '1SJ', '1SS', '1ST', '1SU', '1UA', '1UB', '1UC', '1UF', '1UJ', '1US', '1UU', '1WA', '1WB', '1WC', '1WF', '1WJ', '1WS', '1WU', '2CA', '2CB', '2CC', '2CJ', '2CS', '2EA', '2EB', '2EJ', '2FA', '2FB', '2FC', '2FJ', '2FU', '2HB', '2HC', '2HF', '2HJ', '2HU', '2KA', '2KB', '2KC', '2KF', '2KJ', '2KU', '2MA', '2MB', '2MC', '2MF', '2MJ', '2MS', '2MT', '2PA', '2PB', '2PC', '2PF', '2PJ', '2PU', '2SA', '2SB', '2SC', '2SF', '2SJ', '2UA', '2UB', '2UJ', '2WB', '2WC', '2WF', '2WJ']´

Answer 1

你可以试试这个：

sheet2 = sheet2.filter(regex=(".*F$"))  # Leave only 'F' columns in sheet2

sheet2.columns = [i[:-1] for i in sheet2.columns]  # Remove 'F' in the end for column-wise substraction

result = sheet1 - sheet2  # Substract values

result[result.isnull()] = sheet1  # Leave sheet1 values if there's no appropriate 'F' column in sheet2 

注意：sheet1如果在 中没有带有 'F' 的适当列，则它保持不变的值sheet2。

我像这样创建了你的数据框：

sheet1 = pd.DataFrame({'1C': [1057], '1E': [334], '1F': [3609], '2F': [3609]})

sheet2 = pd.DataFrame({'1CA': [11], '1CB': [381], '1CC': [111], '1CF': [20], '1EF': [10], '1FF': [15]})

Answer 2

sheet1_columns = sheet1.columns.tolist()

sheet2_expected_columns = ['%sF' % (c) for c in sheet1_columns]

common_columns = list(set(sheet2_expected_columns).intersection(set(sheet2.columns.tolist()))

columns_dict = {c:'%sF' % (c) for c in sheet1_columns}

sheet1_with_new_columns_names = sheet1.df.rename(columns=columns_dict)

sheet1_restriction = sheet1_with_new_columns_names[common_columns]

sheets2_restriction = sheets2[common_columns]

result = sheet1_restriction - sheet2_restriction

你能测试一下吗？