我正在从 Web 检索一些 XML,但在提取所需数据时遇到问题。这是 XML:<metadata xmlns="http://musicbrainz.org/ns/mmd-2.0#" xmlns:ext="http://musicbrainz.org/ns/ext#-2.0" created="2013-04-13T16:54:01.107Z"> <artist-list count="2" offset="0"> <artist id="35dac7d2-0b1f-470f-9a5a-c53c8821f6d6" type="Person" ext:score="100"> <name>Eric Prydz</name> <sort-name>Prydz, Eric</sort-name> <gender>male</gender> <country>SE</country> </artist> </artist-list></metadata>我想提取姓名、性别和国家。这是代码:package mainimport ( "encoding/xml" "fmt" "io/ioutil" "net/http")func main() { client := &http.Client{} req, _ := http.NewRequest("GET", "http://www.musicbrainz.org/ws/2/artist/?query=artist:Fred", nil) res, _ := client.Do(req) bs, _ := ioutil.ReadAll(res.Body) var artist Artist xml.Unmarshal(bs, &artist) fmt.Printf("%#v\n", artist)}type Artist struct { Name string `xml: "name"` Gender string `xml: "gender"` Country string `xml: "country"`}但每次我运行这个我总是得到这个:main.Artist{Name:"", Gender:"", Country:""}有人可以指出问题出在哪里吗?
1 回答
Helenr
TA贡献1780条经验 获得超4个赞
好的,问题是,您没有充分描述xml要解组的数据。你的数据看起来更像
struct metadata {
// you need to tag it because go field names can't contain -'s
artists []Artist "artist-list"
}
这样的事情应该有效。基本上,Unmarshal只会看顶层节点,而不是走下来寻找结构。
- 1 回答
- 0 关注
- 172 浏览
添加回答
举报
0/150
提交
取消