我有以下python代码:import networkx as nx def cost(i, j, d, value1, value2): # some operation involving all these values return cost# graph is a networkx graph# src, dst are integers# cost is a callable that is passed 3 values automatically i.e. src, dst and d # d is a dictionary of edge weightspath = nx.dijkstra_path(graph, src, dst, weight=cost)现在我想通过两个值value1,并value2给cost功能。该networkx文件表示,weight可以接受恰好3参数的调用。但我需要value1和value2进行计算。如何才能做到这一点?编辑 使用 functools 的解决方案效果很好。但是,我的函数在一个类中,如下所示:import networkx as nx import functoolsclass Myclass: def cost(self, i, j, d, value2): # some operation involving all these values # also need self # graph is a networkx graph # src, dst are integers # cost is a callable that is passed 3 values automatically i.e. src, dst and d # d is a dictionary of edge weights # path = nx.dijkstra_path(graph, src, dst, cost) cost_partial = functools.partial(cost, self=self, value2=5) path = nx.dijkstra_path(graph, src, dst, cost_partial)使用这种方法,nx.dijkstra_path坚持分配src给self. 因此解释器抱怨self分配了多个值。我需要 self 来计算成本。
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烙印99
TA贡献1829条经验 获得超13个赞
这在很大程度上取决于value1和的含义value2。我建议添加一个可由 networkx 调用的包装器:
def cost_wrapper(i, j, d):
value1 = 0 # set values as needed
value2 = 1
return cost(i, j, d, value1, value2)
并将其提供给 networkx:
path = nx.dijkstra_path(graph, src, dst, weight=cost_wrapper)
或者简单地使它们成为全局变量,而不是参数。
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